In a Young's double slit experiment, fringe width equal to 1 mm is observed. Then the distance of the nearest bright fringe from the central fringe will be :-

Question

In a Young's double slit experiment, fringe width equal to 1 mm is observed. Then the distance of the nearest bright fringe from the central fringe will be :- (A) 0.5 mm (B) 1 mm (C) 2 mm (D) Insufficient data, cannot be determined

Tardigrade Admin · Accepted Answer

Given, β =1mm=(D λ / d) Distance of 1 st bright fringe from the centre xn=2n((D λ /2 d)) For first bright fringe, So x1=((D λ /d))=(D λ /d)=1mm

Q. In a Young's double slit experiment, fringe width equal to 1 mm is observed. Then the distance of the nearest bright fringe from the central fringe will be :-

$0.5 mm$

$1 mm$

$2 mm$

Insufficient data, cannot be determined

Given, $β = 1 mm = (D λ / d)$ Distance of 1 st bright fringe from the centre
$x_{n} = 2 n (\frac{D λ}{2 d})$
For first bright fringe,
So $x_{1} = (\frac{D λ}{d}) = \frac{D λ}{d} = 1 mm$