In a uniform electric field a charge of 3 C experiences a force of 3000 N. The potential difference between two points 1 cm apart along the electric line of force will be

Question

In a uniform electric field a charge of 3 C experiences a force of 3000 N. The potential difference between two points 1 cm apart along the electric line of force will be (A) 10 V (B) 30 V (C) 300 V (D) 100 V

Tardigrade Admin · Accepted Answer

As E=(F/q)=(3000 N/3 C)=1000 N C-1. dr = 1 cm = 10-2 m dV = E(dr) = 1000 × 10-2 = 10 V

Q. In a uniform electric field a charge of $3 C$ experiences a force of $3000 N$ . The potential difference between two points $1 c m$ apart along the electric line of force will be

10 V

30 V

300 V

100 V

As $E = \frac{F}{q} = \frac{3000 N}{3 C} = 1000 N C^{- 1} .$
$d r = 1 c m = 1 0^{- 2} m$
$d V = E (d r) = 1000 \times 1 0^{- 2} = 10 V$

Q. In a uniform electric field a charge of 3C experiences a force of 3000N. The potential difference between two points 1cm apart along the electric line of force will be