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  4. In a uniform electric field a charge of 3 C experiences a force of 3000 N. The potential difference between two points 1 cm apart along the electric line of force will be

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Q. In a uniform electric field a charge of $3\, C$ experiences a force of $3000\, N$. The potential difference between two points $1\, cm$ apart along the electric line of force will be

AIIMSAIIMS 2014Electrostatic Potential and Capacitance

Solution:

As $E=\frac{F}{q}=\frac{3000 N}{3 C}=1000 N C^{-1}.$
$dr = 1 cm = 10^{-2} m$
$dV = E\left(dr\right) = 1000 \times 10^{-2} = 10 V$