In a transformer, number of turns in the primary are 140 and that in the secondary are 280 . If current in primary is 4 A, then that in the secondary is :

Question

In a transformer, number of turns in the primary are 140 and that in the secondary are 280 . If current in primary is 4 A, then that in the secondary is : (A) 4 A (B) 2 A (C) 6 A (D) 10 A

Tardigrade Admin · Accepted Answer

Given: ip=4 A , Np=140, Ns=280 From the formula (ip/is)=(Ns/Np) or (4/is)=(280/140) So, is=2 A

Q. In a transformer, number of turns in the primary are 140 and that in the secondary are 280 . If current in primary is $4 A$ , then that in the secondary is :

$4 A$

$2 A$

$6 A$

$10 A$

Given $: i_{p} = 4 A, N_{p} = 140, N_{s} = 280$
From the formula
$\frac{i _{p}}{i _{s}} = \frac{N _{s}}{N _{p}}$
or $\frac{4}{i _{s}} = \frac{280}{140}$
So, $i_{s} = 2 A$

Q. In a transformer, number of turns in the primary are 140 and that in the secondary are 280 . If current in primary is 4A, then that in the secondary is :

4A

2A

6A

10A