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  4. In a transformer, number of turns in the primary are 140 and that in the secondary are 280 . If current in primary is 4 A, then that in the secondary is :

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Q. In a transformer, number of turns in the primary are 140 and that in the secondary are 280 . If current in primary is $4 A$, then that in the secondary is :

AIEEEAIEEE 2002Alternating Current

Solution:

Given $: i_{p}=4 A ,\,\,\,\, N_{p}=140, N_{s}=280$
From the formula
$\frac{i_{p}}{i_{s}}=\frac{N_{s}}{N_{p}}$
or $\frac{4}{i_{s}}=\frac{280}{140}$
So, $i_{s}=2 A$