Question

In a thin spherical fish bowl of radius $10cm$ filled with water of refractive index $4/3$ . The apparent depth of fish actually at $4cm$ from the centre $C$ from point $E$ is

• A. $5.2cm$
• B. $7.2cm$
• C. $4.2cm$
• D. $3.2cm$

Answer 1

Answer: (A)

As the object is viewed from $E$ , the object distance from curved surface is $=10-4cm$ $=6cm$
By using, $\frac{{\mu }_2}{v}-\frac{{\mu }_1}{u}=\frac{{\mu }_2-{\mu }_1}{R}$
With Sign Convention,
${\mu }_1=\frac{4}{3},{\mu }_2=1,u=-6cm$ , $R=-10cm$
After putting the values,
$\frac{1}{v}-\frac{4/3}{-6}=\frac{1-4/3}{-10}$
$v=-5.2cm$