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  4. In a thin spherical fish bowl of radius 10cm filled with water of refractive index 4/3 . The apparent depth of fish actually at 4cm from the centre C from point E is <img class=img-fluid question-image alt=Question src=https://cdn.tardigrade.in/q/nta/p-twl9sbr5aza6wcev.jpg />

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Q. In a thin spherical fish bowl of radius $10cm$ filled with water of refractive index $4/3$ . The apparent depth of fish actually at $4cm$ from the centre $C$ from point $E$ is
Question

NTA AbhyasNTA Abhyas 2020

Solution:

As the object is viewed from $E$ , the object distance from curved surface is $=10-4cm$ $=6cm$
By using, $\frac{\mu _{2}}{v}-\frac{\mu _{1}}{u}=\frac{\mu _{2} - \mu _{1}}{R}$
With Sign Convention,
$\mu _{1}=\frac{4}{3},\mu _{2}=1,u=-6cm$ , $R=-10cm$
After putting the values,
$\frac{1}{v}-\frac{4/3}{- 6}=\frac{1 - 4/3}{- 10}$
$v=-5.2cm$