In a step-up transformer, the voltage in the primary is 220 V and the current is 5 A. The secondary voltage is found to be 22000 V. The current in the secondary coil (neglect losses) is

Question

In a step-up transformer, the voltage in the primary is 220 V and the current is 5 A. The secondary voltage is found to be 22000 V. The current in the secondary coil (neglect losses) is (A) 5 A (B) 50 A (C) 500 A (D) 0.05 A

Tardigrade Admin · Accepted Answer

(Vs/Vp)=(Ip/Is) ⇒ Is=Ip× (Vp/Vs) =5× (220/22000)=0.05A

Q. In a step-up transformer, the voltage in the primary is $220 V$ and the current is $5 A .$ The secondary voltage is found to be $22000 V .$ The current in the secondary coil (neglect losses) is

$5 A$

$50 A$

$500 A$

$0.05 A$

$\frac{V _{s}}{V _{p}} = \frac{I _{p}}{I _{s}}$
$\Rightarrow I_{s} = I_{p} \times \frac{V _{p}}{V _{s}}$
$= 5 \times \frac{220}{22000} = 0.05 A$

Q. In a step-up transformer, the voltage in the primary is 220V and the current is 5A. The secondary voltage is found to be 22000V. The current in the secondary coil (neglect losses) is

5A

50A

500A

0.05A