In a single slit diffraction pattern, the distance between the first minimum on left and the first minimum on right is 5mm . The screen on which the diffraction pattern is displayed at 80cm from slit. The wavelength is 6000 oversetoA The slit width is about

Question

In a single slit diffraction pattern, the distance between the first minimum on left and the first minimum on right is 5mm . The screen on which the diffraction pattern is displayed at 80cm from slit. The wavelength is 6000 oversetoA The slit width is about (A) 0.348mm (B) 0.192mm (C) 0.567mm (D) 0.960mm

Tardigrade Admin · Accepted Answer

Width of central maxima =(2 λ × D/d)=5mm ⇒ d=((6000 × (10)- 10) (80 × (10)- 2)/2 . 5 × (10)- 2) ⇒ d=0.192mm

Q. In a single slit diffraction pattern, the distance between the first minimum on left and the first minimum on right is $5 mm$ . The screen on which the diffraction pattern is displayed at $80 c m$ from slit. The wavelength is $6000 A o$ The slit width is about

$0.348 mm$

$0.192 mm$

$0.567 mm$

$0.960 mm$

Width of central maxima
$= \frac{2 λ \times D}{d} = 5 mm$
$\Rightarrow d = \frac{( 6000 \times ( 10 ) ^{- 10} ) ( 80 \times ( 10 ) ^{- 2} )}{2.5 \times ( 10 ) ^{- 2}}$
$\Rightarrow d = 0.192 mm$

Q. In a single slit diffraction pattern, the distance between the first minimum on left and the first minimum on right is 5mm . The screen on which the diffraction pattern is displayed at 80cm from slit. The wavelength is 6000Ao The slit width is about

0.348mm

0.192mm

0.567mm

0.960mm