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Q. In a single slit diffraction pattern, the distance between the first minimum on left and the first minimum on right is $5mm$ . The screen on which the diffraction pattern is displayed at $80cm$ from slit. The wavelength is $6000\overset{o}{A}$ The slit width is about

NTA AbhyasNTA Abhyas 2020

Solution:

Width of central maxima
$=\frac{2 \lambda \times D}{d}=5mm$
$\Rightarrow d=\frac{\left(6000 \times \left(10\right)^{- 10}\right) \left(80 \times \left(10\right)^{- 2}\right)}{2 . 5 \times \left(10\right)^{- 2}}$
$\Rightarrow d=0.192mm$