In a reverse biased diode when the applied voltage changes by 1 V, the current is found to change by 0.5 μ A . The reverse bias resistance of the diode is

Question

In a reverse biased diode when the applied voltage changes by 1 V, the current is found to change by 0.5 μ A . The reverse bias resistance of the diode is (A) 2 Ω (B) 200 Ω (C) 2 ×106 Ω (D) 2×105 Ω

Tardigrade Admin · Accepted Answer

Reverse resistance = (Δ V/Δ I) = ( 1/0.5 ×10-6) = 2 ×106 Ω

Q. In a reverse biased diode when the applied voltage changes by $1 V$ , the current is found to change by $0.5 μ A$ . The reverse bias resistance of the diode is

$2Ω$

$200Ω$

$2 \times 1 0^{6} Ω$

$2 \times 1 0^{5} Ω$

Reverse resistance
$= \frac{Δ V}{Δ I}$
$= \frac{1}{0.5 \times 1 0 ^{- 6}}$
$= 2 \times 1 0^{6} Ω$

Q. In a reverse biased diode when the applied voltage changes by 1V, the current is found to change by 0.5μA . The reverse bias resistance of the diode is

2Ω

200Ω

2×106Ω

2×105Ω