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Q. In a reverse biased diode when the applied voltage changes by $1\, V$, the current is found to change by $0.5\, \mu\,A$ . The reverse bias resistance of the diode is

KCETKCET 2007Semiconductor Electronics: Materials Devices and Simple Circuits

Solution:

Reverse resistance
$= \frac{\Delta V}{\Delta I}$
$ = \frac{ 1}{0.5 \times10^{-6}} $
$ = 2 \times10^{6} \Omega$