In a region of uniform electric field of intensity E , an electron of mass me is released from rest. The distance travelled by the electron in a time t is

Question

In a region of uniform electric field of intensity E , an electron of mass me is released from rest. The distance travelled by the electron in a time t is (A)  (2met2/e)  (B)  (eEt2/2me)  (C)  (megt2/eE)  (D)  (2Et2/eme)

Tardigrade Admin · Accepted Answer

The force on electron in the electric field F =e E ∴ Acceleration, a =(F/me)=(e E/m0) Now, from equation of motion, S=(1/2) a t2=(1/2) (e E/me) t2 where, t= time

Q. In a region of uniform electric field of intensity $E$ , an electron of mass $m_{e}$ is released from rest. The distance travelled by the electron in a time $t$ is

$\frac{2 m _{e} t ^{2}}{e}$

$\frac{e E t ^{2}}{2 m _{e}}$

$\frac{m _{e} g t ^{2}}{e E}$

$\frac{2 E t ^{2}}{e m _{e}}$

The force on electron in the electric field
$F = e E$
$∴$ Acceleration, $a = \frac{F}{m _{e}} = \frac{e E}{m _{0}}$
Now, from equation of motion,
$S = \frac{1}{2} a t^{2} = \frac{1}{2} \frac{e E}{m _{e}} t^{2}$
where, $t =$ time

Q. In a region of uniform electric field of intensity E , an electron of mass me​ is released from rest. The distance travelled by the electron in a time t is

e2me​t2​

2me​eEt2​

eEme​gt2​

eme​2Et2​