In a reaction, A + B → C, the rate expression is R = k [A] [B]2. If the concentration of both the reactant is doubled at constant volume, then the rate of the reaction will be

Question

In a reaction, A + B → C, the rate expression is R = k [A] [B]2. If the concentration of both the reactant is doubled at constant volume, then the rate of the reaction will be (A) eight times (B) double (C) quadruple (D) triple

Tardigrade Admin · Accepted Answer

Given, R=k[A][B]2 when [A]' =[2 A] and [B]'=[2 B] R' =k[2 A][2 B]2 =k[2 A] 4[B]2=8 k[A][B]2 ⇒ R'=8 R Thus, the rate will become eight times

Q. In a reaction, $A + B \to C$ , the rate expression is $R = k [A] [B]^{2}$ . If the concentration of both the reactant is doubled at constant volume, then the rate of the reaction will be

eight times

double

quadruple

triple

Given, $R = k [A] [B]^{2}$

when $[A]^{'} = [2 A]$ and $[B]^{'} = [2 B]$

$R^{'} = k [2 A] [2 B]^{2}$

$= k [2 A] 4 [B]^{2} = 8 k [A] [B]^{2}$

$\Rightarrow R^{'} = 8 R$

Thus, the rate will become eight times

Q. In a reaction, A+B→C, the rate expression is R=k[A][B]2. If the concentration of both the reactant is doubled at constant volume, then the rate of the reaction will be