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Chemistry
In a reaction, A + B → C, the rate expression is R = k [A] [B]2. If the concentration of both the reactant is doubled at constant volume, then the rate of the reaction will be
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Q. In a reaction, $A + B \to C$, the rate expression is $R = k [A] [B]^2$. If the concentration of both the reactant is doubled at constant volume, then the rate of the reaction will be
UPSEE
UPSEE 2015
Chemical Kinetics
A
eight times
25%
B
double
33%
C
quadruple
35%
D
triple
6%
Solution:
Given, $R=k[A][B]^{2}$
when $[A]' =[2 A] $ and $[B]'=[2 B] $
$ R' =k[2 A][2 B]^{2} $
$=k[2 A] 4[B]^{2}=8 k[A][B]^{2}$
$ \Rightarrow \, R'=8 R $
Thus, the rate will become eight times