In a reaction 2X → Y, the concentration of X decreases from 3.0 moles/litre to 2.0 moles/litre in 5 minutes. The rate of reaction is

Question

In a reaction 2X → Y, the concentration of X decreases from 3.0 moles/litre to 2.0 moles/litre in 5 minutes. The rate of reaction is (A) 0.1 mol L-1 min-1 (B) 5 mol L-1 min-1 (C) 1 mol L-1 min-1 (D) 0.5 mol L-1 min-1

Tardigrade Admin · Accepted Answer

Rate =-(1/2) (Δ[X]/Δ t) =-(1/2)((3-2)/5)=-0.1 mol L-1 min-1 Negative sign signifies the decrease in concentration.

Q. In a reaction $2 X \to Y$ , the concentration of $X$ decreases from $3.0$ moles/litre to $2.0$ moles/litre in $5$ minutes. The rate of reaction is

$0.1 m o l L^{- 1} mi n^{- 1}$

$5 m o l L^{- 1} mi n^{- 1}$

$1 m o l L^{- 1} mi n^{- 1}$

$0.5 m o l L^{- 1} mi n^{- 1}$

Rate $= - \frac{1}{2} \frac{Δ [ X ]}{Δ t}$
$= - \frac{1}{2} \frac{( 3 - 2 )}{5} = - 0.1 m o l L^{- 1} mi n^{- 1}$
Negative sign signifies the decrease in concentration.

Q. In a reaction 2X→Y, the concentration of X decreases from 3.0 moles/litre to 2.0 moles/litre in 5 minutes. The rate of reaction is

0.1molL−1min−1

5molL−1min−1

1molL−1min−1

0.5molL−1min−1