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Chemistry
In a reaction 2X → Y, the concentration of X decreases from 3.0 moles/litre to 2.0 moles/litre in 5 minutes. The rate of reaction is
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Q. In a reaction $2X \to Y$, the concentration of $X$ decreases from $3.0$ moles/litre to $2.0$ moles/litre in $5$ minutes. The rate of reaction is
Chemical Kinetics
A
$0.1\, mol\, L^{-1} min^{-1}$
62%
B
$5\, mol\, L^{-1} min^{-1}$
8%
C
$1 \,mol\, L^{-1} min^{-1}$
16%
D
$0.5\, mol\, L^{-1} min^{-1}$
14%
Solution:
Rate $=-\frac{1}{2} \frac{\Delta\left[X\right]}{\Delta t}$
$=-\frac{1}{2}\frac{\left(3-2\right)}{5}=-0.1 \,mol\, L^{-1} min^{-1}$
Negative sign signifies the decrease in concentration.