In a process, 701 J of heat is absorbed by a system and 394 J of work is done by the system. What is the change in internal energy (in J) for the process?

Question

In a process, 701 J of heat is absorbed by a system and 394 J of work is done by the system. What is the change in internal energy (in J) for the process? (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Given, q = + 701 J (heat is absorbed, heance q is positive.)

W = - 394 J (work is done by the system, hence W is negative.)

By first law of thermodynamics;

Internal energy change,

Δ U = q + w

= + 701 J + (-394 J ) = + 307 J.

Hence, internal energy of the system increases by 307 J.

Q. In a process, 701 J of heat is absorbed by a system and 394 J of work is done by the system. What is the change in internal energy (in J) for the process?

Given, q = + 701 J (heat is absorbed, heance q is positive.) W = - 394 J (work is done by the system, hence W is negative.) By first law of thermodynamics; Internal energy change, ΔU=q+w = + 701 J + (-394 J ) = + 307 J. Hence, internal energy of the system increases by 307 J.

Given, q = + 701 J (heat is absorbed, heance q is positive.)

W = - 394 J (work is done by the system, hence W is negative.)

By first law of thermodynamics;

Internal energy change, $Δ U = q + w$

= + 701 J + (-394 J ) = + 307 J.

Hence, internal energy of the system increases by 307 J.