1. Tardigrade
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  3. Chemistry
  4. In a process, 701 J of heat is absorbed by a system and 394 J of work is done by the system. What is the change in internal energy (in J) for the process?

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Q. In a process, 701 J of heat is absorbed by a system and 394 J of work is done by the system. What is the change in internal energy (in J) for the process?

NTA AbhyasNTA Abhyas 2020Thermodynamics

Solution:

Given, q = + 701 J (heat is absorbed, heance q is positive.)

W = - 394 J (work is done by the system, hence W is negative.)

By first law of thermodynamics;

Internal energy change, $\Delta \text{U} = \text{q} + \text{w}$

= + 701 J + (-394 J ) = + 307 J.

Hence, internal energy of the system increases by 307 J.