In a platinum resistance thermometer, the resistances of the wire at ice point and steam point are of 4 Ω and 4.25 Ω respectively. When the thermometer is kept in a hot water bath, whose temperatqre is not known, the resistance of the wire is found to be 4.5 Ω. The temperature of the hot water bath is

Question

In a platinum resistance thermometer, the resistances of the wire at ice point and steam point are of 4 Ω and 4.25 Ω respectively. When the thermometer is kept in a hot water bath, whose temperatqre is not known, the resistance of the wire is found to be 4.5 Ω. The temperature of the hot water bath is (A) 150°C (B) 100°C (C) 300°C (D) 350°C

Tardigrade Admin · Accepted Answer

(4.5-4/4.25-4)=(T-O/100) T=200° C

$15 0^{\circ} C$

$10 0^{\circ} C$

$30 0^{\circ} C$

$35 0^{\circ} C$

$20 0^{\circ} C$

$\frac{4.5 - 4}{4.25 - 4} = \frac{T - O}{100}$
$T = 20 0^{\circ} C$

150∘C

100∘C

300∘C

350∘C

200∘C