1. Tardigrade
  2. Question
  3. Physics
  4. In a platinum resistance thermometer, the resistances of the wire at ice point and steam point are of 4 Ω and 4.25 Ω respectively. When the thermometer is kept in a hot water bath, whose temperatqre is not known, the resistance of the wire is found to be 4.5 Ω. The temperature of the hot water bath is

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Q. In a platinum resistance thermometer, the resistances of the wire at ice point and steam point are of $4 \,\Omega$ and $4.25\,\Omega$ respectively. When the thermometer is kept in a hot water bath, whose temperatqre is not known, the resistance of the wire is found to be $4.5\,\Omega$. The temperature of the hot water bath is

KEAMKEAM 2020

Solution:

$\frac{4.5-4}{4.25-4}=\frac{T-O}{100}$
$T=200^{\circ} C$