In a one component second order reaction, if the concentration of the reactant is reduced to half, the rate

Question

In a one component second order reaction, if the concentration of the reactant is reduced to half, the rate (A) increases two times (B) increases four times (C) decreases to one half (D) decreases to one fourth

Tardigrade Admin · Accepted Answer

For second order reaction, 2Aarrow Product Rate of reaction, r=k[A]2. If the concentration is reduced to half, i.e.(A/2) ∴ r'=k[(A/2)]2 r' =(1/4)k[A]2 or r' =(1/4)r

Q. In a one component second order reaction, if the concentration of the reactant is reduced to half, the rate

increases two times

increases four times

decreases to one half

decreases to one fourth

For second order reaction,
$2 A \to$ Product
Rate of reaction, $r = k [A]^{2}$ .
If the concentration is reduced to half, $i . e . \frac{A}{2}$
$∴ r^{'} = k [\frac{A}{2}]^{2}$
$r^{'} = \frac{1}{4} k [A]^{2}$
or $r^{'} = \frac{1}{4} r$

Q. In a one component second order reaction, if the concentration of the reactant is reduced to half, the rate

increases two times

increases four times

decreases to one half

decreases to one fourth

For second order reaction, 2A→ Product Rate of reaction, r=k[A]2. If the concentration is reduced to half, i.e.2A​ ∴r′=k[2A​]2 r′=41​k[A]2 or r′=41​r

For second order reaction,
$2 A \to$ Product
Rate of reaction, $r = k [A]^{2}$ .
If the concentration is reduced to half, $i . e . \frac{A}{2}$
$∴ r^{'} = k [\frac{A}{2}]^{2}$
$r^{'} = \frac{1}{4} k [A]^{2}$
or $r^{'} = \frac{1}{4} r$