In a hydrogen atom, an electron moves in a circular orbit of radius 5.2 × 10-11 m and produces a magnetic induction of 12.56 T at its centre. The current produced by the motion of the electron will be

Question

In a hydrogen atom, an electron moves in a circular orbit of radius 5.2 × 10-11 m and produces a magnetic induction of 12.56 T at its centre. The current produced by the motion of the electron will be (A) 6.53 × 10-3 A (B) 13.25 × 10-10 A (C) 9.6 × 106 A (D) 1.04 × 10-3 A

Tardigrade Admin · Accepted Answer

Magnetic field on a current-carrying in a circular orbit i.e., B=(μ0 I/2 R) ∴ I=(B × 2 R/μ0)=(12.56 × 2 × 5.2 × 10-11/4 π × 10-7) =1.04 × 10-3 A

Q. In a hydrogen atom, an electron moves in a circular orbit of radius $5.2 \times 1 0^{- 11} m$ and produces a magnetic induction of $12.56 T$ at its centre. The current produced by the motion of the electron will be

$6.53 \times 1 0^{- 3} A$

$13.25 \times 1 0^{- 10} A$

$9.6 \times 1 0^{6} A$

$1.04 \times 1 0^{- 3} A$

Magnetic field on a current-carrying in a circular orbit
i.e., $B = \frac{μ _{0} I}{2 R}$
$∴ I = \frac{B \times 2 R}{μ _{0}} = \frac{12.56 \times 2 \times 5.2 \times 1 0 ^{- 11}}{4 π \times 1 0 ^{- 7}}$
$= 1.04 \times 1 0^{- 3} A$

Q. In a hydrogen atom, an electron moves in a circular orbit of radius 5.2×10−11m and produces a magnetic induction of 12.56T at its centre. The current produced by the motion of the electron will be

6.53×10−3A

13.25×10−10A

9.6×106A

1.04×10−3A