Question

In a hydrogen atom, an electron moves in a circular orbit of radius $5.2 \times 10^{-11} \, m$ and produces a magnetic induction of $12.56 \,T$ at its centre. The current produced by the motion of the electron will be

• A. $6.53 \times 10^{-3} \, A$
• B. $13.25 \times 10^{-10} \,A$
• C. $9.6 \times 10^{6} \,A$
• D. $1.04 \times 10^{-3} \,A$

Answer 1

Answer: (D)

Magnetic field on a current-carrying in a circular orbit
i.e., $ B=\frac{\mu_{0} I}{2 R}$
$\therefore I=\frac{B \times 2 R}{\mu_{0}}=\frac{12.56 \times 2 \times 5.2 \times 10^{-11}}{4 \pi \times 10^{-7}}$
$=1.04 \times 10^{-3} A$