Tardigrade
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Tardigrade
Question
Chemistry
In a cyclic process, heat transfers are +14.7 kJ ,-25.2 kJ -3.56 kJ and +31.5 kJ . What is the net work done in the net cyclic process?
Q. In a cyclic process, heat transfers are
+
14.7
k
J
,
−
25.2
k
J
−
3.56
k
J
and
+
31.5
k
J
.
What is the net work done in the net cyclic process?
2358
195
Thermodynamics
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A
10 kJ
0%
B
-10 kJ
8%
C
-17.44 kJ
23%
D
+17.44 kJ
69%
Solution:
In the cyclic process
Δ
W
cyc
+
Δ
q
cyc
=
0
or
Δ
W
cyc
=
−
Δ
q
cyc
=
−
[
14.7
−
25.2
−
3.56
+
31.5
]
k
J
or
Δ
W
cyc
=
−
17.44
k
J