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Q. In a cyclic process, heat transfers are $+14.7 \,kJ ,-25.2 \,kJ$ $-3.56\, kJ$ and $+31.5 \,kJ .$ What is the net work done in the net cyclic process?

Thermodynamics

Solution:

In the cyclic process $\Delta W_{\text {cyc }}+\Delta q_{\text {cyc }}=0$

or $ \Delta W_{\text {cyc }}=-\Delta q_{ cyc }=-[14.7-25.2-3.56+31.5] kJ$

or $\Delta W_{ cyc }=-17.44 \,kJ$