In a Cu-voltameter, mass deposited in 30s is m gm. If the time-current graph is shown in the following figure What is the electrochemical equivalent of Cu?

Question

In a Cu-voltameter, mass deposited in 30s is m gm. If the time-current graph is shown in the following figure <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/c-4dvwxcfc6jymuss9.jpg" /> What is the electrochemical equivalent of Cu? (A) m/2 (B) m/3 (C) m/4 (D) (m/63.5)

Tardigrade Admin · Accepted Answer

Total charge passed in 30 sec. =(1/2)× 100× 10+100× 10+100× 10+(1/2)× 100× 10 =3× 100× 10mA× s =3000× 10- 3amp text s= text3C W=ZQ So Z=(W/Q)=(m/3)

Q. In a $C u$ -voltameter, mass deposited in $30 s$ is $m g m$ . If the time-current graph is shown in the following figure

What is the electrochemical equivalent of $C u$ ?

m/2

m/3

m/4

$\frac{m}{63.5}$

Total charge passed in $30$ sec.
$= \frac{1}{2} \times 100 \times 10 + 100 \times 10 + 100 \times 10 + \frac{1}{2} \times 100 \times 10$
$= 3 \times 100 \times 10 m A \times s$
$= 3000 \times 1 0^{- 3} am p s = 3C$
$W = ZQ$
So $Z = \frac{W}{Q} = \frac{m}{3}$

Q. In a Cu-voltameter, mass deposited in 30s is mgm. If the time-current graph is shown in the following figure What is the electrochemical equivalent of Cu?

m/2

m/3

m/4

63.5m​

Total charge passed in 30 sec. =21​×100×10+100×10+100×10+21​×100×10 =3×100×10mA×s =3000×10−3amp s=3C W=ZQ So Z=QW​=3m​

Q. In a $C u$ -voltameter, mass deposited in $30 s$ is $m g m$ . If the time-current graph is shown in the following figure

What is the electrochemical equivalent of $C u$ ?

$\frac{m}{63.5}$

Total charge passed in $30$ sec.
$= \frac{1}{2} \times 100 \times 10 + 100 \times 10 + 100 \times 10 + \frac{1}{2} \times 100 \times 10$
$= 3 \times 100 \times 10 m A \times s$
$= 3000 \times 1 0^{- 3} am p s = 3C$
$W = ZQ$
So $Z = \frac{W}{Q} = \frac{m}{3}$