In a compound C, H and N are present in 9:13.5 by weight. If molecular weight of the compound is 108 , then the molecular formula on the compound is

Question

In a compound C, H and N are present in 9:13.5 by weight. If molecular weight of the compound is 108 , then the molecular formula on the compound is (A)  C6H6N2 (B) C3H4N (C)  C6H8N2 (D) C9H12N3

Tardigrade Admin · Accepted Answer

C H N 9 1 3.5 9/12 = 0.75 1/1=1 3.5/14 = 0.25 (0.75/0.25) = 3 (1/0.25) = 4 (0.25/0.25) = 1 So, empirical formulaa = C3H4N n = (108/54) = 2 Molecular formula = (C3H4N)2 = C6H8N2

Q. In a compound $C, H$ and $N$ are present in $9 : 13.5$ by weight. If molecular weight of the compound is $108$ , then the molecular formula on the compound is

$C_{6} H_{6} N_{2}$

$C_{3} H_{4} N$

$C_{6} H_{8} N_{2}$

$C_{9} H_{12} N_{3}$

C H N

9 1 3.5

9/12 = 0.75 1/1=1 3.5/14 = 0.25

$\frac{0.75}{0.25} = 3$ $\frac{1}{0.25} = 4$ $\frac{0.25}{0.25} = 1$

So, empirical formulaa $= C_{3} H_{4} N$
$n = \frac{108}{54} = 2$
Molecular formula $= (C_{3} H_{4} N)_{2} = C_{6} H_{8} N_{2}$

C	H	N
9	1	3.5
9/12 = 0.75	1/1=1	3.5/14 = 0.25
$\frac{0.75}{0.25} = 3$	$\frac{1}{0.25} = 4$	$\frac{0.25}{0.25} = 1$

Q. In a compound C,H and N are present in 9:13.5 by weight. If molecular weight of the compound is 108 , then the molecular formula on the compound is

C6​H6​N2​

C3​H4​N

C6​H8​N2​

C9​H12​N3​