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Q. In a compound $ C,\,\,H $ and $ N $ are present in $ 9:13.5 $ by weight. If molecular weight of the compound is $ 108 $ , then the molecular formula on the compound is

Rajasthan PMTRajasthan PMT 2007Organic Chemistry – Some Basic Principles and Techniques

Solution:

C H N
9 1 3.5
9/12 = 0.75 1/1=1 3.5/14 = 0.25
$\frac{0.75}{0.25} = 3$ $\frac{1}{0.25} = 4$ $\frac{0.25}{0.25} = 1$

So, empirical formulaa $= C_3H_4N$
$n = \frac{108}{54} = 2$
Molecular formula $ = (C_3H_4N)_2 = C_6H_8N_2$