In a coagulating experiment, CH3CHO of AgNo3 is mixed with distilled water and 0.2 M solution of an electrolyte AB, so that the total volume is 20 mL. All solutions containing 5.4 mL of AB coagulate within 2 min. The flocculation value sof AB (in millimol) is

Question

In a coagulating experiment, CH3CHO of AgNo3 is mixed with distilled water and 0.2 M solution of an electrolyte AB, so that the total volume is 20 mL. All solutions containing 5.4 mL of AB coagulate within 2 min. The flocculation value sof AB (in millimol) is (A) 5 (B) 50 (C) 54 (D) None of the above

Tardigrade Admin · Accepted Answer

Flocculation value is the amount of electrolyte, in millimoles required to bring about complete coagulation of 1 L of colloidal solution. Amount of AB in 5.4 mL of 0.2 M AB =(5.4× 0.2/1000)=1.08× 10-3mol 20 text mL of As2S3 requires AB for coagulation =1.08× 10-3mol 1000mL of As As2S3 requires AB (i.e., flocculation value) =(1.08× 10-3/20)× 1000 =0.054 text mol=54 milfimol

Q. In a coagulating experiment, CH3​CHO of AgNo3​ is mixed with distilled water and 0.2 M solution of an electrolyte AB, so that the total volume is 20 mL. All solutions containing 5.4 mL of AB coagulate within 2 min. The flocculation value sof AB (in millimol) is

5

50

54

None of the above

Q. In a coagulating experiment, $C H_{3} C H O$ of $A g N o_{3}$ is mixed with distilled water and 0.2 M solution of an electrolyte AB, so that the total volume is 20 mL. All solutions containing 5.4 mL of AB coagulate within 2 min. The flocculation value sof AB (in millimol) is