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Q. In a coagulating experiment, $ C{{H}_{3}}CHO $ of $ AgN{{o}_{3}} $ is mixed with distilled water and 0.2 M solution of an electrolyte AB, so that the total volume is 20 mL. All solutions containing 5.4 mL of AB coagulate within 2 min. The flocculation value sof AB (in millimol) is

BVP MedicalBVP Medical 2014

Solution:

Flocculation value is the amount of electrolyte, in millimoles required to bring about complete coagulation of 1 L of colloidal solution. Amount of AB in 5.4 mL of 0.2 M AB $ =\frac{5.4\times 0.2}{1000}=1.08\times {{10}^{-3}}mol $ $ 20\text{ }mL $ of $ A{{s}_{2}}{{S}_{3}} $ requires AB for coagulation $ =1.08\times {{10}^{-3}}mol $ $ 1000mL $ of As $ A{{s}_{2}}{{S}_{3}} $ requires AB (i.e., flocculation value) $ =\frac{1.08\times {{10}^{-3}}}{20}\times 1000 $ $ =0.054\text{ }mol=54 $ milfimol