In a circular conducting coil, when current increases from 2 A to 18 A in 0.05 s, the induced e.m.f. is 20 V. The self inductance of the coil is

Question

In a circular conducting coil, when current increases from 2 A to 18 A in 0.05 s, the induced e.m.f. is 20 V. The self inductance of the coil is (A) 62.5 mH (B) 6.25 mH (C) 50 mH (D) None of these

Tardigrade Admin · Accepted Answer

|e|=L (d i/d t) ⇒ 20 =L × ((18-2)/0.05) ⇒ L=62.5 mH

Q. In a circular conducting coil, when current increases from $2 A$ to $18 A$ in $0.05 s$ , the induced e.m.f. is $20 V$ . The self inductance of the coil is

62.5 mH

6.25 mH

50 mH

None of these

$∣ e ∣ = L \frac{d i}{d t} \Rightarrow 20$
$= L \times \frac{( 18 - 2 )}{0.05} \Rightarrow L = 62.5 m H$

Q. In a circular conducting coil, when current increases from 2A to 18A in 0.05s, the induced e.m.f. is 20V. The self inductance of the coil is