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  4. In a circular conducting coil, when current increases from 2 A to 18 A in 0.05 s, the induced e.m.f. is 20 V. The self inductance of the coil is

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Q. In a circular conducting coil, when current increases from $2\, A$ to $18\, A$ in $0.05\, s$, the induced e.m.f. is $20\, V$. The self inductance of the coil is

Electromagnetic Induction

Solution:

$|e|=L \frac{d i}{d t} \Rightarrow 20$
$=L \times \frac{(18-2)}{0.05} \Rightarrow L=62.5\, mH$