Question

In a carnot engine, the temperature of reservoir is $527^{\circ }C$ and that of sink is $200K$. If the work done by the engine when it transfers heat from reservoir to sink is $12000kJ$, the quantity of heat absorbed by the engine from reservoir is _______$\times 10^{6}J$

Answer 1

Answer: 16

$\left(T_2\right)T_{\sin k}=200K$
$\left(T_1\right)T_{\text{Reservoir }}=527+273=800K$
$W=12000KJ=12\times 10^{6}J$
$Q_1=?$
$\eta =1-\frac{T_2}{T_1}=\frac{W}{Q_1}=1-\frac{200}{800}=\frac{12\times 10^6}{Q_1}$
$\frac{3}{4}=\frac{12\times 10^6}{Q_1}=Q_1=16\times 10^{6}J$