Question

In a carnot engine, the temperature of reservoir is $527^{\circ} C$ and that of sink is $200 \,K$. If the work done by the engine when it transfers heat from reservoir to sink is $12000 \,kJ$, the quantity of heat absorbed by the engine from reservoir is _______$\times 10^{6} J$

Answer 1

$\left(T_{2}\right) T_{\sin k}=200 \,K$
$\left(T_{1}\right) T_{\text {Reservoir }}=527+273=800\, K$
$W=12000 \,KJ =12 \times 10^{6} J$
$Q_{1}=?$
$\eta=1-\frac{T_{2}}{T_{1}}=\frac{W}{Q_{1}}=1-\frac{200}{800}=\frac{12 \times 10^{6}}{Q_{1}}$
$\frac{3}{4}=\frac{12 \times 10^{6}}{Q_{1}}=Q_{1}=16 \times 10^{6} J$