Question

In a balanced equation,
$H_{2}S{O}_4+xHI\to H_{2}S+y{I}_2+z{H}_{2}O$
the value of $x,y$ and $z$ are respectively

• A. 3, 5, 2
• B. 4, 8, 5
• C. 8, 4, 4
• D. 5, 3, 4

Answer 1

Answer: (C)

The equation is,
$H_{2}S{O}_4+xHI\to H_{2}S+y{I}_2+z{H}_{2}O$
The above equation is balanced by oxidation number method. In this method, firstly the change in oxidation number of elements is counted and then, balanced them.

Now, balanced the hydrogen and oxygen.
$H_{2}S{O}_4+8HI\to H_{2}S+4I_2+4H_{2}O$
So, the value of $x,y$ and $z$ are 8, 4 and 4 respectively.