Question

In a balanced equation,
$H_{2}SO_{4}+xHI \rightarrow H_{2}S +yI_{2}+zH_{2}O$
the value of $ x,\,y$ and $z$ are respectively

• A. 3, 5, 2
• B. 4, 8, 5
• C. 8, 4, 4
• D. 5, 3, 4

Answer 1

Answer: (C)

The equation is,
$H_{2}SO_{4}+xHI \rightarrow H_{2}S +yI_{2}+zH_{2}O$
The above equation is balanced by oxidation number method. In this method, firstly the change in oxidation number of elements is counted and then, balanced them.

Now, balanced the hydrogen and oxygen.
$H_{2}SO_{4}+8HI \rightarrow H_{2}S+ 4I_{2}+4H_{2}O$
So, the value of $x,\,y$ and $z$ are 8, 4 and 4 respectively.