In a 0.25 litre tube dissociation of 4 moles of NO takes place. If its degree of dissociation is 10 %. The value of K for reaction 2NO leftharpoons N2 + O2 is:

Question

In a 0.25 litre tube dissociation of 4 moles of NO takes place. If its degree of dissociation is 10 %. The value of K for reaction 2NO leftharpoons N2 + O2 is: (A)  (1/(18)2) (B)  (1/(8)2) (C) (1/16) (D) (1/32)

Tardigrade Admin · Accepted Answer

Correct answer is (a) (1/(18)2)

Q. In a $0.25$ litre tube dissociation of $4$ moles of $NO$ takes place. If its degree of dissociation is $10%$ . The value of $K$ for reaction $2 NO ⇌ N_{2} + O_{2}$ is:

$\frac{1}{( 18 ) ^{2}}$

$\frac{1}{( 8 ) ^{2}}$

$\frac{1}{16}$

$\frac{1}{32}$

Correct answer is (a) $\frac{1}{( 18 ) ^{2}}$

Q. In a 0.25 litre tube dissociation of 4 moles of NO takes place. If its degree of dissociation is 10%. The value of K for reaction 2NO⇌N2​+O2​ is:

(18)21​

(8)21​

161​

321​