Impedance of circuit when a resistance R and inductor of inductance L are connected in series in an A.C. circuit of frequency f is:

Question

Impedance of circuit when a resistance R and inductor of inductance L are connected in series in an A.C. circuit of frequency f is: (A)  √R2+2π 2f2L2  (B)  √R2+4π 2f2L2  (C)  √R+4π 2f2L2  (D)  √R+2π 2f2L2

Tardigrade Admin · Accepted Answer

Here: Resistance =R, inductance =L and frequency of the circuit =f As the effective resistance or impedance Z=√R2+ω 2L2 (where ω = angular frequency of A.C circuits equal to 2π f ) Hence impedance Z=√R2+(2π f)2L2=√R2+4π 2f2L2

Q. Impedance of circuit when a resistance R and inductor of inductance L are connected in series in an A.C. circuit of frequency $f$ is:

$R^{2} + 2 π^{2} f^{2} L^{2}$

$R^{2} + 4 π^{2} f^{2} L^{2}$

$R + 4 π^{2} f^{2} L^{2}$

$R + 2 π^{2} f^{2} L^{2}$

Here: Resistance $= R,$ inductance $= L$ and frequency of the circuit $= f$ As the effective resistance or impedance $Z = R^{2} + ω^{2} L^{2}$ (where $ω =$ angular frequency of A.C circuits equal to $2 π f$ ) Hence impedance $Z = R^{2} + (2 π f)^{2} L^{2} = R^{2} + 4 π^{2} f^{2} L^{2}$

Q. Impedance of circuit when a resistance R and inductor of inductance L are connected in series in an A.C. circuit of frequency f is:

R2+2π2f2L2​

R2+4π2f2L2​

R+4π2f2L2​

R+2π2f2L2​