Question

Column I		Column II
A	He	i	High electron affinity
B	Cl	ii	Most electropositive element
C	Ca	iii	Strongest reducing agent
D	Li	iv	Highest ionisation energy

The correct match of contents in Column I with those in Column II is

• A. $A-iii,B-i,C-ii,D-iv$
• B. $A-iv,B-iii,C-ii,D-i$
• C. $A-ii,B-iv,C-i,D-iii$
• D. $A-i,B-ii,C-iii,D-iv$
• E. $A-iv,B-i,C-ii,D-iii$

Answer 1

Answer: (E)

(i) For noble gases (eg. He), ionization energy is highest due to their completely filled electronic configuration.
(ii) Generally electron affinity increases in a period (from IA to VII A group) and decreases in a group but electron affinity is highest for chlorine $(Cl)$ (due to smaller size and high electron density of fluorine).
(iii) The ionization energy is lowest for Li, so it can lose electrons very easily, thus it behaves as a strongest reducing agent.
(iv) Electropositive character generally decreases in a period (from left to right) and increases in a group (on moving down), thus Ca is the most electropositive element among the given. Hence, on the basis of above facts, the correct matches are (A)-iv (B)-i (C)-ii (D)-iii