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Q.

Column I Column II

A He i High electron affinity

B Cl ii Most electropositive element

C Ca iii Strongest reducing agent

D Li iv Highest ionisation energy

The correct match of contents in Column I with those in Column II is

KEAMKEAM 2008Classification of Elements and Periodicity in Properties

A

$A-iii, B-i, C-ii, D-iv$

6%

B

$A-iv, B-iii, C-ii, D-i$

14%

C

$A-ii, B-iv, C-i, D-iii$

12%

D

$A-i, B-ii, C-iii, D-iv$

6%

E

$A-iv, B-i, C-ii, D-iii$

6%

Solution:

(i) For noble gases (eg. He), ionization energy is highest due to their completely filled electronic configuration.
(ii) Generally electron affinity increases in a period (from IA to VII A group) and decreases in a group but electron affinity is highest for chlorine $ (Cl) $ (due to smaller size and high electron density of fluorine).
(iii) The ionization energy is lowest for Li, so it can lose electrons very easily, thus it behaves as a strongest reducing agent.
(iv) Electropositive character generally decreases in a period (from left to right) and increases in a group (on moving down), thus Ca is the most electropositive element among the given. Hence, on the basis of above facts, the correct matches are (A)-iv (B)-i (C)-ii (D)-iii