If z1=6+3 i and z2=2-i, then (z1/z2) is equal to (1/a)(9+12 i) The value of 'a' is

Question

If z1=6+3 i and z2=2-i, then (z1/z2) is equal to (1/a)(9+12 i) The value of 'a' is (A) 1 (B) 2 (C) 4 (D) 5

Tardigrade Admin · Accepted Answer

(z1/z2)=(6+3 i/2-i)=(6+3 i/2-i) × (2+i/2+i)=(12+6 i+6 i-3/4-i2) =(9+12 i/5)=(1/5)(9+12 i) ≡ (1/a)(9+12 i ) Hence, a = 5

Q. If $z_{1} = 6 + 3 i$ and $z_{2} = 2 - i$ , then $\frac{z _{1}}{z _{2}}$ is equal to $\frac{1}{a} (9 + 12 i)$ The value of $^{'} a^{'}$ is