Question

If $y=x^2+sinx+\frac{1}{x^2}$, then $\frac{dy}{dx}$ is equal to

• A. $2x-cosx+2$
• B. $x-2x^2+cosx$
• C. $2x+cosx-(2/x^3)$
• D. $(2/x^3)-cosx$

Answer 1

Answer: (C)

We have, $y=x^2+sinx+\frac{1}{x^2}$
$\therefore \frac{dy}{dx}=2x+cosx+\left(-2\right)x^{-3}$
$=2x+cosx-\frac{2}{x^3}$