Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. If $y=x^{2}+sinx+\frac{1}{x^{2}}$, then $\frac{dy}{dx}$ is equal to

Limits and Derivatives

Solution:

We have, $y=x^{2}+sinx+\frac{1}{x^{2}}$
$\therefore \frac{dy}{dx}=2x+cos\,x+\left(-2\right)x^{-3}$
$=2x+cos\,x-\frac{2}{x^{3}}$