If y=f(x) is an odd periodic function defined from R to R such that f(x)= begincasesx2+2 x, 0 ≤ x ≤ 1 6-3 x, 1

Question

If y=f(x) is an odd periodic function defined from R to R such that f(x)= begincasesx2+2 x, 0 ≤ x ≤ 1 6-3 x, 1< x ≤ 2 endcaseswith period 4, then the value of f (2015) equals (A) 0 (B) 3 (C) 2 (D) - 3

Tardigrade Admin · Accepted Answer

f (2015)= f (4 × 503+3)= f (3-4)= f (-1)=- f (1)=-3

Q. If $y = f (x)$ is an odd periodic function defined from $R$ to $R$ such that $f (x) = {x^{2} + 2 x, 6 - 3 x, 0 \leq x \leq 1 1 < x \leq 2$ with period 4, then the value of f (2015) equals

0

3

2

- 3

$f (2015) = f (4 \times 503 + 3) = f (3 - 4) = f (- 1) = - f (1) = - 3$

Q. If y=f(x) is an odd periodic function defined from R to R such that f(x)={x2+2x,6−3x,​0≤x≤11<x≤2​with period 4, then the value of f (2015) equals

0

3

2

- 3

f(2015)=f(4×503+3)=f(3−4)=f(−1)=−f(1)=−3

Q. If $y = f (x)$ is an odd periodic function defined from $R$ to $R$ such that $f (x) = {x^{2} + 2 x, 6 - 3 x, 0 \leq x \leq 1 1 < x \leq 2$ with period 4, then the value of f (2015) equals

$f (2015) = f (4 \times 503 + 3) = f (3 - 4) = f (- 1) = - f (1) = - 3$