1. Tardigrade
  2. Question
  3. Mathematics
  4. If y=f(x) is an odd periodic function defined from R to R such that f(x)= begincasesx2+2 x, 0 ≤ x ≤ 1 6-3 x, 1< x ≤ 2 endcaseswith period 4, then the value of f (2015) equals

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Q. If $y=f(x)$ is an odd periodic function defined from $R$ to $R$ such that $f(x)=\begin{cases}x^2+2 x, & 0 \leq x \leq 1 \\ 6-3 x, & 1< x \leq 2\end{cases}$with period 4, then the value of f (2015) equals

Relations and Functions - Part 2

Solution:

$f (2015)= f (4 \times 503+3)= f (3-4)= f (-1)=- f (1)=-3$