Question

If $xmol{L}^{-1}$ is the solubility of $KAl{\left(S{O}_4\right)}_2$ then $K_{sp}$ is equal to

• A. $x^3$
• B. $4x^4$
• C. $x^4$
• D. $4x^3$

Answer 1

Answer: (B)

$KAl{\left(S{O}_4\right)}_2⟶\underset{x}{K^{+}}+\underset{x}{A{l}^{3+}}+\underset{2x}{2S{O}_4^{2-}}$
$K_{sp}=\left[K^{+}\right]\left[A{l}^{3+}\right]{\left[S{O}_4^{2-}\right]}^2$
$=(x)(x)(2x{)}^2=4x^4$