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  4. If x mol L -1 is the solubility of KAl ( SO 4)2 then K sp is equal to

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Q. If $x \,mol \,L ^{-1}$ is the solubility of $KAl \left( SO _{4}\right)_{2}$ then $K_{ sp }$ is equal to

Bihar CECEBihar CECE 2011Equilibrium

Solution:

$KAl \left( SO _{4}\right)_{2} \longrightarrow \underset{x}{K ^{+}}+ \underset{x}{Al ^{3+}}+\underset{2x}{2 SO _{4}^{2-}}$
$K_{ sp }=\left[ K ^{+}\right]\left[ Al ^{3+}\right]\left[ SO _{4}^{2-}\right]^{2}$
$=(x)(x)(2 x)^{2}=4 x^{4}$