If x3+(1/x3)=62, then find the value of √x3+(1/√x3). The following steps are involved in solving the above problem. Arrange them in sequential order. (A) ∴(√x3+(1/√x3))2=62+2=64 (B) ⇒(√x3+(1/√x3))=√64=8 (C) ∴(√x3+(1/√x3))2=x3+(1/x3)+2 (D) But x3+(1/x3)=62

Question

If x3+(1/x3)=62, then find the value of √x3+(1/√x3). The following steps are involved in solving the above problem. Arrange them in sequential order. (A) ∴(√x3+(1/√x3))2=62+2=64 (B) ⇒(√x3+(1/√x3))=√64=8 (C) ∴(√x3+(1/√x3))2=x3+(1/x3)+2 (D) But x3+(1/x3)=62 (A) CABD (B) ABCD (C) ACDB (D) CDAB

Tardigrade Admin · Accepted Answer

(C),(D),(A) and (B) is the required sequential order.

CABD

$A BC D$

$A C D B$

$C D A B$

$(C), (D), (A)$ and $(B)$ is the required sequential order.

Q. If x3+x31​=62, then find the value of x3​+x3​1​. The following steps are involved in solving the above problem. Arrange them in sequential order. (A) ∴(x3​+x3​1​)2=62+2=64 (B) ⇒(x3​+x3​1​)=64​=8 (C) ∴(x3​+x3​1​)2=x3+x31​+2 (D) But x3+x31​=62

CABD

ABCD

ACDB

CDAB

(C),(D),(A) and (B) is the required sequential order.

$A BC D$

$A C D B$

$C D A B$

$(C), (D), (A)$ and $(B)$ is the required sequential order.