Q. If $x^{2} - x + 1 = 0$ , then value of $x^{3 n}$ is

2022 200 Complex Numbers and Quadratic Equations Report Error

A

0

100%

B

-1

0%

C

1

0%

D

-1,1

0%

Solution:

Since $x^{2} - x + 1 = 0$
$∴ (x - 1) (x^{2} - x + 1) = 0$
$\Rightarrow x^{3} - 1 = 0$
$\Rightarrow x^{3} = 1$ ,
$∴ x^{3 n} = 1$